Function to get last day for a month

February 22, 2005

>>Script Language and Platform: SQL Server
This script will create a UDF that will show the maximum day for a given date or month that you supply. Format date supplied as parameter should be : "MM/DD/YYYY"; it will produce a single int value. In example if you supplied date like "02/13/2004", the UDF will show you : 28, which means 28 days in february, 2004.

Author: catur bharata

CREATE  FUNCTION last_day (@date DATETIME)
RETURNS INT
AS
BEGIN

DECLARE @n_month INT, @n_date DATETIME, @n_year INT, @l_day INT
DECLARE @i INT

SET @n_month= MONTH(@date)
SET @n_year = YEAR(@date)
SET @i = 1
IF @n_year % 4 = 0
		SET @l_day = 
		(CASE @n_month
		WHEN 1 THEN 31
		WHEN 2 THEN 29
		WHEN 3 THEN 31
		WHEN 4 THEN 30
		WHEN 5 THEN 31
		WHEN 6 THEN 30
		WHEN 7 THEN 31
		WHEN 8 THEN 31
		WHEN 9 THEN 30
		WHEN 10 THEN 31
		WHEN 11 THEN 30
		ELSE 31
		END)

IF @n_year % 4 > 0
		SET @l_day = 
		(CASE @n_month
		WHEN 1 THEN 31
		WHEN 2 THEN 28
		WHEN 3 THEN 31
		WHEN 4 THEN 30
		WHEN 5 THEN 31
		WHEN 6 THEN 30
		WHEN 7 THEN 31
		WHEN 8 THEN 31
		WHEN 9 THEN 30
		WHEN 10 THEN 31
		WHEN 11 THEN 30
		ELSE 31
		END)
RETURN(@l_day)
END

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