Find all numbers in a string

>>Script Language and Platform: SQL Server
This function finds all the numbers in a string.

Example.

select dbo.udf_findallnumbers (’12sfg34′)
–results
1234
select dbo.udf_findallnumbers (‘asas123’)
–results
123
select dbo.udf_findallnumbers (‘assd123jdh556jdfd4j56j78’)
–results
12355645678
select dbo.udf_findallnumbers (‘sadasd’)
–results
0
select dbo.udf_findallnumbers (‘sadasds65’)
–results
65
create table test (name varchar(100))
insert into test select ‘A2b4b2b5bb6bb8bb9’
insert into test select ‘MAK9974’
insert into test select ‘Eiko36DKoike’
select dbo.udf_findallnumbers (name) from test
–results
2425689
9974
36

Author: MAK

Create function dbo.udf_findallnumbers (@inputstring varchar(100))
returns bigint
as
begin
–Author : MAK
–Contact: mak_999@yahoo.com
–Date: Feb 2, 2004
–declare variables
declare @count1 smallint
declare @len1 smallint
declare @word varchar(100)
declare @char1 char
–Assignment
set @word=”
set @count1=1
set @len1 = datalength(@inputstring)
	While @count1 <=@len1
	begin
	set @char1 =substring(@inputstring,@count1,1)
	if ascii(@char1) between 48 and 57
	begin
	set @word=@word+substring(@inputstring,@count1,1)
	end
	set @count1=@count1+1
	end
return convert(bigint,@word)
end

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