Find all numbers in a string

>>Script Language and Platform: SQL Server
This function finds all the numbers in a string.

Example.

select dbo.udf_findallnumbers (’12sfg34′)

–results

1234

select dbo.udf_findallnumbers (‘asas123’)

–results

123

select dbo.udf_findallnumbers (‘assd123jdh556jdfd4j56j78’)

–results

12355645678

select dbo.udf_findallnumbers (‘sadasd’)

–results

0

select dbo.udf_findallnumbers (‘sadasds65’)

–results

65

create table test (name varchar(100))

insert into test select ‘A2b4b2b5bb6bb8bb9’

insert into test select ‘MAK9974’

insert into test select ‘Eiko36DKoike’
select dbo.udf_findallnumbers (name) from test

–results

2425689

9974

36

Author: MAK

Create function dbo.udf_findallnumbers (@inputstring varchar(100))

returns bigint

as

begin

–Author : MAK

–Contact: mak_999@yahoo.com

–Date: Feb 2, 2004

–declare variables

declare @count1 smallint

declare @len1 smallint

declare @word varchar(100)

declare @char1 char

–Assignment

set @word=”

set @count1=1

set @len1 = datalength(@inputstring)

	While @count1 <=@len1

	begin

	set @char1 =substring(@inputstring,@count1,1)

	if ascii(@char1) between 48 and 57

	begin

	set @word=@word+substring(@inputstring,@count1,1)

	end

	set @count1=@count1+1

	end

return convert(bigint,@word)
end

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