Format Date based on supplied Format String

MSSQL
This function will take a format string that has YYYY MM and DD in the string and replace it
with the appropriate date element.

Examples
— Select dbo.FmtDate (‘YYYYMMDD’,getdate())
— Returns 20071214
— Select dbo.FmtDate (‘YYYY-MM-DD’,getdate())
— Returns 2007-12-14
— Select dbo.FmtDate (‘MM/DD/YYYY’,’10/3/2007′)
— Returns 10/03/2007
— Select dbo.FmtDate (‘YYYYMM’,getdate())
— Returns 200712
— Select dbo.FmtDate (‘DD’,getdate())
— Returns 14
— Select dbo.FmtDate (‘Year:YYYY Month:MM Day:DD’,getdate())
— Returns ‘Year:2007 Month:12 Day:14’

Author: Todd Harnar

— Author:              Todd Harnar
— Email:               tharnar@hotmail.com
— Code may be used as long as Author and Email address
— remains as part of comments.
— Create date: 12/14/2007
— Description: Return date based on format string
— This function will take a format string that has
— YYYY MM and DD in the string and replace it
— with the appropriate date element
—
—
        — Examples
        — Select dbo.FmtDate (‘YYYYMMDD’,getdate())
        — Returns 20071214
        — Select dbo.FmtDate (‘YYYY-MM-DD’,getdate())
        — Returns 2007-12-14
        — Select dbo.FmtDate (‘MM/DD/YYYY’,’10/3/2007′)
        — Returns 10/03/2007
        — Select dbo.FmtDate (‘YYYYMM’,getdate())
        — Returns 200712
        — Select dbo.FmtDate (‘DD’,getdate())
        — Returns 14
        — Select dbo.FmtDate (‘Year:YYYY Month:MM Day:DD’,getdate())
        — Year:2007 Month:12 Day:14′
— =============================================
CREATE FUNCTION [dbo].[FmtDate]
(
        — String should contain at least one of the following date elements
        — YYYY, MM or DD
        @FmtStr varchar(50),
        — Date to be formatted
        @Dt datetime
)
RETURNS varchar(50)
AS
BEGIN
        — String to hold formatted date
        Declare @tmpstr as varchar(50)
        — Element values of supplied date
        Declare @tmpMonth as varchar(2)
        Declare @tmpDay as varchar(2)
        Declare @tmpYear as varchar(4)
        Set @tmpStr = @fmtStr
        — Determine Date Elements
        Set @tmpDay = RIGHT((‘0’ + convert(varchar(2),DAY(@dt))),2)
        Set @tmpMonth = RIGHT((‘0’+ convert(varchar(2),MONTH(@dt))),2)
        Set @tmpYear = convert(varchar(4),YEAR(@dt))
        — Replace Date Elements in supplied format string
        SELECT @tmpstr = REPLACE(@tmpstr,’YYYY’,@tmpYear)
        SELECT @tmpStr = REPLACE(@tmpstr,’MM’,@tmpMonth)
        SELECT @tmpStr = REPLACE(@tmpstr,’DD’,@tmpDay)
        –Return result
        RETURN @tmpstr
END

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